Solutions Hints and Tips of Business Mathematics Grade 12 ( NEB)
Core Derivative Problems
Example 4: Finding Turning Points
Question: Find the stationary point and points of inflection of y = x^3 - 3x^2 - 9.
1. Finding Stationary Points:
- First derivative: 3x^2 - 6x.
- Set to zero: 3x(x - 2) = 0. This gives x = 0 and x = 2.
- Tip: These are your critical points where the graph changes direction.
2. Finding Point of Inflection:
- Second derivative: 6x - 6.
- Set to zero: 6x = 6, which gives x = 1.
- Tip: At x = 1, the curve stops bending one way and starts bending the other.
- First derivative: 3x^2 - 6x.
- Set to zero: 3x(x - 2) = 0. This gives x = 0 and x = 2.
- Tip: These are your critical points where the graph changes direction.
2. Finding Point of Inflection:
- Second derivative: 6x - 6.
- Set to zero: 6x = 6, which gives x = 1.
- Tip: At x = 1, the curve stops bending one way and starts bending the other.
Example 3: Intervals of Growth
Question: Find the intervals for which f(x) = x^4 - 2x^2 is increasing or decreasing.
Steps:
- Derivative: 4x^3 - 4x. Factor it: 4x(x - 1)(x + 1).
- Critical points: -1, 0, and 1.
- Trick: Test a number in each zone.
- Derivative: 4x^3 - 4x. Factor it: 4x(x - 1)(x + 1).
- Critical points: -1, 0, and 1.
- Trick: Test a number in each zone.
- If derivative is Negative (-): Decreasing.
- If derivative is Positive (+): Increasing.
Business Optimization Derivatives
Example 1: Minimizing Average Cost
Question: If Total Cost C = 1/3 Q^3 - 3Q^2 + 9Q, at what output level is Average Cost minimum?
Steps:
- First, find Average Cost (AC) by dividing C by Q: AC = 1/3 Q^2 - 3Q + 9.
- To find the minimum, take the derivative of AC: 2/3 Q - 3.
- Set to zero: 2/3 Q = 3, which gives Q = 4.5.
- Hint: The second derivative of AC is 2/3 (Positive), which proves this is a minimum.
- First, find Average Cost (AC) by dividing C by Q: AC = 1/3 Q^2 - 3Q + 9.
- To find the minimum, take the derivative of AC: 2/3 Q - 3.
- Set to zero: 2/3 Q = 3, which gives Q = 4.5.
- Hint: The second derivative of AC is 2/3 (Positive), which proves this is a minimum.
Condition for Max Profit
Key Concept: Profit is highest when Marginal Revenue (MR) = Marginal Cost (MC).
Trick to Solve:
1. Find Revenue (Price * Quantity).
2. Find MR by differentiating Revenue.
3. Find MC by differentiating Total Cost.
4. Set MR = MC and solve for Q.
1. Find Revenue (Price * Quantity).
2. Find MR by differentiating Revenue.
3. Find MC by differentiating Total Cost.
4. Set MR = MC and solve for Q.
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